Optimal. Leaf size=167 \[ -\frac{16 (b+2 c x) \left (4 a c C+16 A c^2+3 b^2 C\right )}{15 \left (b^2-4 a c\right )^3 \sqrt{a+b x+c x^2}}-\frac{2 \left (x \left (C \left (b^2-2 a c\right )+2 A c^2\right )+b c \left (\frac{a C}{c}+A\right )\right )}{5 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^{5/2}}+\frac{2 (b+2 c x) \left (4 a C+16 A c+\frac{3 b^2 C}{c}\right )}{15 \left (b^2-4 a c\right )^2 \left (a+b x+c x^2\right )^{3/2}} \]
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Rubi [A] time = 0.106591, antiderivative size = 167, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.182, Rules used = {1660, 12, 614, 613} \[ -\frac{16 (b+2 c x) \left (4 a c C+16 A c^2+3 b^2 C\right )}{15 \left (b^2-4 a c\right )^3 \sqrt{a+b x+c x^2}}-\frac{2 \left (x \left (C \left (b^2-2 a c\right )+2 A c^2\right )+b c \left (\frac{a C}{c}+A\right )\right )}{5 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^{5/2}}+\frac{2 (b+2 c x) \left (4 a C+16 A c+\frac{3 b^2 C}{c}\right )}{15 \left (b^2-4 a c\right )^2 \left (a+b x+c x^2\right )^{3/2}} \]
Antiderivative was successfully verified.
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Rule 1660
Rule 12
Rule 614
Rule 613
Rubi steps
\begin{align*} \int \frac{A+C x^2}{\left (a+b x+c x^2\right )^{7/2}} \, dx &=-\frac{2 \left (b c \left (A+\frac{a C}{c}\right )+\left (2 A c^2+\left (b^2-2 a c\right ) C\right ) x\right )}{5 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^{5/2}}-\frac{2 \int \frac{16 A c+4 a C+\frac{3 b^2 C}{c}}{2 \left (a+b x+c x^2\right )^{5/2}} \, dx}{5 \left (b^2-4 a c\right )}\\ &=-\frac{2 \left (b c \left (A+\frac{a C}{c}\right )+\left (2 A c^2+\left (b^2-2 a c\right ) C\right ) x\right )}{5 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^{5/2}}-\frac{\left (16 A c+4 a C+\frac{3 b^2 C}{c}\right ) \int \frac{1}{\left (a+b x+c x^2\right )^{5/2}} \, dx}{5 \left (b^2-4 a c\right )}\\ &=-\frac{2 \left (b c \left (A+\frac{a C}{c}\right )+\left (2 A c^2+\left (b^2-2 a c\right ) C\right ) x\right )}{5 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^{5/2}}+\frac{2 \left (16 A c+4 a C+\frac{3 b^2 C}{c}\right ) (b+2 c x)}{15 \left (b^2-4 a c\right )^2 \left (a+b x+c x^2\right )^{3/2}}+\frac{\left (8 \left (16 A c^2+3 b^2 C+4 a c C\right )\right ) \int \frac{1}{\left (a+b x+c x^2\right )^{3/2}} \, dx}{15 \left (b^2-4 a c\right )^2}\\ &=-\frac{2 \left (b c \left (A+\frac{a C}{c}\right )+\left (2 A c^2+\left (b^2-2 a c\right ) C\right ) x\right )}{5 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^{5/2}}+\frac{2 \left (16 A c+4 a C+\frac{3 b^2 C}{c}\right ) (b+2 c x)}{15 \left (b^2-4 a c\right )^2 \left (a+b x+c x^2\right )^{3/2}}-\frac{16 \left (16 A c^2+3 b^2 C+4 a c C\right ) (b+2 c x)}{15 \left (b^2-4 a c\right )^3 \sqrt{a+b x+c x^2}}\\ \end{align*}
Mathematica [A] time = 1.85438, size = 148, normalized size = 0.89 \[ \frac{2 \left (\left (b^2-4 a c\right ) (b+2 c x) (a+x (b+c x)) \left (4 a c C+16 A c^2+3 b^2 C\right )-8 c (b+2 c x) (a+x (b+c x))^2 \left (4 a c C+16 A c^2+3 b^2 C\right )-3 \left (b^2-4 a c\right )^2 \left (a C (b-2 c x)+A c (b+2 c x)+b^2 C x\right )\right )}{15 c \left (b^2-4 a c\right )^3 (a+x (b+c x))^{5/2}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.051, size = 316, normalized size = 1.9 \begin{align*}{\frac{512\,A{c}^{5}{x}^{5}+128\,Ca{c}^{4}{x}^{5}+96\,C{b}^{2}{c}^{3}{x}^{5}+1280\,Ab{c}^{4}{x}^{4}+320\,Cab{c}^{3}{x}^{4}+240\,C{b}^{3}{c}^{2}{x}^{4}+1280\,Aa{c}^{4}{x}^{3}+960\,A{x}^{3}{b}^{2}{c}^{3}+320\,C{a}^{2}{c}^{3}{x}^{3}+480\,Ca{b}^{2}{c}^{2}{x}^{3}+180\,C{b}^{4}c{x}^{3}+1920\,Aab{c}^{3}{x}^{2}+160\,A{x}^{2}{b}^{3}{c}^{2}+480\,C{a}^{2}b{c}^{2}{x}^{2}+400\,Ca{b}^{3}c{x}^{2}+30\,C{b}^{5}{x}^{2}+960\,A{a}^{2}{c}^{3}x+480\,Aa{b}^{2}{c}^{2}x-20\,A{b}^{4}cx+480\,C{a}^{2}{b}^{2}cx+40\,Ca{b}^{4}x+480\,A{a}^{2}b{c}^{2}-80\,Aa{b}^{3}c+6\,A{b}^{5}+192\,C{a}^{3}bc+16\,C{a}^{2}{b}^{3}}{960\,{a}^{3}{c}^{3}-720\,{a}^{2}{b}^{2}{c}^{2}+180\,a{b}^{4}c-15\,{b}^{6}} \left ( c{x}^{2}+bx+a \right ) ^{-{\frac{5}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 77.4996, size = 1224, normalized size = 7.33 \begin{align*} -\frac{2 \,{\left (8 \, C a^{2} b^{3} + 3 \, A b^{5} + 240 \, A a^{2} b c^{2} + 16 \,{\left (3 \, C b^{2} c^{3} + 4 \, C a c^{4} + 16 \, A c^{5}\right )} x^{5} + 40 \,{\left (3 \, C b^{3} c^{2} + 4 \, C a b c^{3} + 16 \, A b c^{4}\right )} x^{4} + 10 \,{\left (9 \, C b^{4} c + 24 \, C a b^{2} c^{2} + 64 \, A a c^{4} + 16 \,{\left (C a^{2} + 3 \, A b^{2}\right )} c^{3}\right )} x^{3} + 5 \,{\left (3 \, C b^{5} + 40 \, C a b^{3} c + 192 \, A a b c^{3} + 16 \,{\left (3 \, C a^{2} b + A b^{3}\right )} c^{2}\right )} x^{2} + 8 \,{\left (12 \, C a^{3} b - 5 \, A a b^{3}\right )} c + 10 \,{\left (2 \, C a b^{4} + 24 \, A a b^{2} c^{2} + 48 \, A a^{2} c^{3} +{\left (24 \, C a^{2} b^{2} - A b^{4}\right )} c\right )} x\right )} \sqrt{c x^{2} + b x + a}}{15 \,{\left (a^{3} b^{6} - 12 \, a^{4} b^{4} c + 48 \, a^{5} b^{2} c^{2} - 64 \, a^{6} c^{3} +{\left (b^{6} c^{3} - 12 \, a b^{4} c^{4} + 48 \, a^{2} b^{2} c^{5} - 64 \, a^{3} c^{6}\right )} x^{6} + 3 \,{\left (b^{7} c^{2} - 12 \, a b^{5} c^{3} + 48 \, a^{2} b^{3} c^{4} - 64 \, a^{3} b c^{5}\right )} x^{5} + 3 \,{\left (b^{8} c - 11 \, a b^{6} c^{2} + 36 \, a^{2} b^{4} c^{3} - 16 \, a^{3} b^{2} c^{4} - 64 \, a^{4} c^{5}\right )} x^{4} +{\left (b^{9} - 6 \, a b^{7} c - 24 \, a^{2} b^{5} c^{2} + 224 \, a^{3} b^{3} c^{3} - 384 \, a^{4} b c^{4}\right )} x^{3} + 3 \,{\left (a b^{8} - 11 \, a^{2} b^{6} c + 36 \, a^{3} b^{4} c^{2} - 16 \, a^{4} b^{2} c^{3} - 64 \, a^{5} c^{4}\right )} x^{2} + 3 \,{\left (a^{2} b^{7} - 12 \, a^{3} b^{5} c + 48 \, a^{4} b^{3} c^{2} - 64 \, a^{5} b c^{3}\right )} x\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.2866, size = 659, normalized size = 3.95 \begin{align*} -\frac{{\left ({\left (2 \,{\left (4 \,{\left (\frac{2 \,{\left (3 \, C b^{2} c^{3} + 4 \, C a c^{4} + 16 \, A c^{5}\right )} x}{b^{6} c^{3} - 12 \, a b^{4} c^{4} + 48 \, a^{2} b^{2} c^{5} - 64 \, a^{3} c^{6}} + \frac{5 \,{\left (3 \, C b^{3} c^{2} + 4 \, C a b c^{3} + 16 \, A b c^{4}\right )}}{b^{6} c^{3} - 12 \, a b^{4} c^{4} + 48 \, a^{2} b^{2} c^{5} - 64 \, a^{3} c^{6}}\right )} x + \frac{5 \,{\left (9 \, C b^{4} c + 24 \, C a b^{2} c^{2} + 16 \, C a^{2} c^{3} + 48 \, A b^{2} c^{3} + 64 \, A a c^{4}\right )}}{b^{6} c^{3} - 12 \, a b^{4} c^{4} + 48 \, a^{2} b^{2} c^{5} - 64 \, a^{3} c^{6}}\right )} x + \frac{5 \,{\left (3 \, C b^{5} + 40 \, C a b^{3} c + 48 \, C a^{2} b c^{2} + 16 \, A b^{3} c^{2} + 192 \, A a b c^{3}\right )}}{b^{6} c^{3} - 12 \, a b^{4} c^{4} + 48 \, a^{2} b^{2} c^{5} - 64 \, a^{3} c^{6}}\right )} x + \frac{10 \,{\left (2 \, C a b^{4} + 24 \, C a^{2} b^{2} c - A b^{4} c + 24 \, A a b^{2} c^{2} + 48 \, A a^{2} c^{3}\right )}}{b^{6} c^{3} - 12 \, a b^{4} c^{4} + 48 \, a^{2} b^{2} c^{5} - 64 \, a^{3} c^{6}}\right )} x + \frac{8 \, C a^{2} b^{3} + 3 \, A b^{5} + 96 \, C a^{3} b c - 40 \, A a b^{3} c + 240 \, A a^{2} b c^{2}}{b^{6} c^{3} - 12 \, a b^{4} c^{4} + 48 \, a^{2} b^{2} c^{5} - 64 \, a^{3} c^{6}}}{15 \,{\left (c x^{2} + b x + a\right )}^{\frac{5}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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